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schepotkina [342]
3 years ago
11

A polynomial equation has only imaginary roots and no real root. Which options CANNOT be the degree of that polynomial? (Select

all that apply.)
A. 2
B. 3
C. 4
D. 6
E. 7
F. 8
Mathematics
2 answers:
puteri [66]3 years ago
7 0

we know that

Imaginary roots will come in pairs, and so the degree must be even.

therefore

the answer is

options

B. 3

E. 7

VMariaS [17]3 years ago
5 0

Answer:

Options B and E

Step-by-step explanation:

Given that a polynomial equation has only imaginary roots.

Since the polynomial has real coefficients, the imaginary roots can only occur in pairs as each conjugate of the other.

In other words, the polynomial can have only an even number of imaginary roots.

Since all roots are imaginary, the polynomial can have degrees as even number only

either 2 or 4 or 6 or 8

It is not possible for the polynomial to have degrees as 3,7

Hence answers are

options B and E

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Answer:

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

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Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

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Now,

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A = {BG, GB}

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Now,

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∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9

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