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Natali5045456 [20]

3 years ago

6

The two photos are both for the same question please help I dont know how to solve the revered graph

1 answer:

SVETLANKA909090 [29]3 years ago

4 0

Answer:

point b is plotted incorrectly

Step-by-step explanation:

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Represent the set of numbers as decimals on the number line {5 3/10, 5 1/10, 5 and if you answer more than needed thank you

Alina [70]

Answer:

(0.53 > 0.51) both less than 1 while 5 is greater than both

Step-by-step explanation:

$\frac{53}{10} = .53, \frac{51}{10} = .51.$ and 5

the number line has two sides, with the left side for negative numbers while the right side is for positive numbers.

<u> </u>

-5 -4 -3 -2 -1 -.53 -.51 0 .51 .53 1 2 3 4 5

By studying the number line above all decimal numbers greater than 0 but less than 1 are from 0, .1, .2,.........,.98, .99, 1.00 which is also the same as 1 because all numbers greater than 1 has an invisible point at its right side like 2., 3. which also means 2, 3 while negative number are all less than 0

7 0

3 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

Write the equation of the parabola that has the vertex at point (2,7) and passes through

Anton [14]

Answer:

$f(x) = \frac{4}{3} (x - 2) ^{2} + 7$

Step-by-step explanation:

the answer is :- .

$f(x) = \frac{4}{3} (x - 2) ^{2} + 7$

6 0

2 years ago

Write an equation in slope-intercept form of the line that passes through (-1, 4) and (0, 2).

arsen [322]

Answer:

$y=-2x+2$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Determine the slope</u>

$m=\frac{y_2-y_1}{x_2-x_1}$ where the two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-1, 4) and (0, 2)

$=\frac{2-4}{0-(-1)}\\=\frac{-2}{0+1}\\=\frac{-2}{1}\\= -2$

Therefore, the slope of the line is -2. Plug this into $y=mx+b$ :

$y=-2x+b$

<u>2) Determine the y-intercept</u>

$y=-2x+b$

Recall that the y-intercept is the value of y when the line crosses the y-axis, meaning that the y-intercept occurs when x is equal to 0.

One of the given points is (0,2). Notice how y=2 when x=0. Therefore, the y-intercept of the line is 2.

Plug this back into the equation:

$y=-2x+2$

I hope this helps!

6 0

3 years ago

Evaluate the expression when x = –11. 2x – 19 <br> a. 41 <br> b. 3 <br> c. –3 <br> d. –41

WARRIOR [948]

2(-11)-19
-22-19
-41

D is the answer

5 0

3 years ago