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3 years ago

Write an equation for the line that passes through the given point 1. (-3,1), (0,-8)

Mathematics

2 answers:

aniked [119]3 years ago

8 0

Answer:

y=-3x-8

Step-by-step explanation:

that's the answer

aleksklad [387]3 years ago

5 0

Answer:

y = - 3x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 3, 1) and (x₂, y₂ ) = (0, - 8)

m = $\frac{-8-1}{0+3}$ = $\frac{-9}{3}$ = - 3

The line crosses the y- axis at (0, - 8 ) ⇒ c = - 8

y = - 3x - 8 ← equation of line

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The ratio of the corresponding linear measures of two similar cans of vegetables is 2 to 3. The smaller can has a surface area o

Shalnov [3]

Answer:

$405 {cm}^{2}$

Step-by-step explanation:

We have that, the ratio of the corresponding linear measures of two similar cans of vegetables is 2 to 3.

We want to find the area of the larger can, if the smaller can has a surface area of 180 square centimeters.

We know the scale factor is

$k = \frac{3}{2} = 1.5$

To find the surface area of the larger can, we multiply the square of the scale factor by 180.

This implies that, the surface area of the larger can is

$1.5^{2} \times 180 = 405 {cm}^{2}$

7 0

4 years ago

What are the zeros of the polynomial function f(x)=x^3-9x^2+29x?

Flauer [41]

Answer:

x=0, x= (9+i square root35)/2, x= (9-i square root 35)/2

Step-by-step explanation:

6 0

3 years ago

Determine the equation of the tangent of the hyperbola that is parallel to the given line:

marin [14]

The tangent line to the curve has slope equal to $\frac{\mathrm dy}{\mathrm dx}$ . Use implicit differentiation to find this derivative.

$9x^2-4y^2=32$

$\implies18x-16y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{-18x}{-16y}=\dfrac{9x}{8y}$

The given line in slope-intercept form is

$9x+2y-1=0\implies y=\dfrac{1-9x}2$

and has slope -9/2. Any line parallel to this one has the same slope. The tangent to the hyperbola has this slope at points (<em>x</em>, <em>y</em>) such that

$-\dfrac92=\dfrac{9x}{8y}\implies x=-4y$

Find the points on the hyperbola where this condition is met.

$9(-4y)^2-4y^2=140y^2=32\implies y^2=\dfrac{32}{140}\implies y=\pm\sqrt{\dfrac8{35}}\implies x=\pm4\sqrt{\dfrac8{35}}$

Then use the point-slop formula to build the equations of these tangents:

$y\mp\sqrt{\dfrac8{35}}=-\dfrac92\left(x\pm4\sqrt{\dfrac8{35}}\right)$

8 0

3 years ago

Okay so I'm doing distributive property equations and I can't figure this one out negative 7(5k-4)=negative 7

irina1246 [14]

Answer:

-7(5k-4) = -7

-35k + 28 = -7

-35k = -35

k = 1

4 0

3 years ago

Read 2 more answers

If 14x = 14−−√13, what value of x makes this equation true?

maxonik [38]

Answer:

x = 26.89352

Step-by-step explanation:

1. remove parenthesis

2. divide both sides by 14

7 0

3 years ago