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3 years ago

2y = 2x = 8 y = x + 4

Mathematics

1 answer:

padilas [110]3 years ago

4 0

Answer:

I love algebra anyways

the ans is in the picture with the steps how i got it

(hope that helps can i plz have brainlist it will make my day :D hehe)

Step-by-step explanation:

You might be interested in

What does 45 - 4x equal

xxTIMURxx [149]

Let y = 0 to find the x-intercept(s).

0 = 45 − 4x

*Then subtract 45 from both sides*
-45 = -4x

*Next, DIVIDE both sides by -4*

-45
—— = x
-4

*NEXT, realize that TWO NEGATIVES MAKE A POSITIVE *

45. 4
——— = x {FLIP} x=——-
4. 45.

y-Intercept

Let x = 0 to find the y-intercept(s).

y = 45 −4(0)

NEXT, SIMPLIFY:

y=45

7 0

3 years ago

Which side of the equation 12.6v = 12 - 15.5v would you isolate the variable terms? Why?

lozanna [386]

The left side, because you only need to move one thing, and you don't need to subtract after that. (you can add, much more easier)

hope this helps

4 0

3 years ago

David and Denise share n pears in the ratio 4:9. If n = 39 how many pears does David have?

saul85 [17]

Answer:

David has 12 pears.

Step-by-step explanation:

4 + 9 = 13

39 / 13 = 3

3 x 4 = 12

3 x 9 = 27

6 0

2 years ago

Can someone answer this

attashe74 [19]

Answer:

Step-by-step explanation:

axis: x= 2

vertex: (2,3)

6 0

3 years ago

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

3 years ago

2y = 2x = 8 y = x + 4​

2y = 2x = 8 y = x + 4