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Ne4ueva [31]
3 years ago
15

A hypothetical square grows so that the length of its diagonals are increasing at a rate of 8m/min. How fast is the area of the

square increasing when the sides are 8m each.

Mathematics
2 answers:
ad-work [718]3 years ago
7 0

Answer: The area of the square is increasing at a rate of 90.4 m2/min (square meters/minute)

Step-by-step explanation: Please see the attachments below

Svetach [21]3 years ago
7 0

Answer:

The area of the square is increasing at 90.51m^2/min

Step by step explanation:

Given;

Change in diagonal length ∆d = 8m/min

Length l = 8m

When l = 8m

d^2 = 2l^2 = 2×8^2 = 128

d = √128

Area of a square = l^2 = (d^2)/2

d = diagonal

Change in area = ∆A = dA/dd

∆A = 2 × d/2 × ∆d = d×∆d

∆A = √128 × 8 = 90.51m^2/min

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3. I opened a compound interest account with $300 at 2%. How much money will be in the
MArishka [77]

Answer:

there will be 408$ at the end of 18 months

Step-by-step explanation:

2% of 300 is 6 and 6 x 18 = 108. 108 + 300 = 408

8 0
3 years ago
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Which of the following is equivalent to<br> (5) 3<br> O 54<br> O 54<br> 05<br> O V5
IrinaK [193]

Answer:

D. \sqrt[3]{5^7}

Step-by-step explanation:

The formula for this conversion is:

a^\frac{x}{n}=\sqrt[n]{a^x}

Substitute the values you currently have.

5^\frac{7}{3}=\sqrt[n]{a^x}

Since we know that

a = 5

x = 7

n = 3

Fill the square root with this.

5^\frac{7}{3}=\sqrt[3]{5^7}

4 0
2 years ago
Given the diagram below, what is the length of segment EF
bekas [8.4K]
Let x = length of segment EF.

Assume that
(a) line segments AD,  EF, and BC are parallel, and
(b) the vertical distance between AD and EF is equal to the vertical distance between EF and BC.

Then from similarity between geometric shapes, we can write
\frac{2.2}{x} = \frac{x}{4.8}
x^{2} =(2.2)(4.8)=10.56
x=3.2   (nearest tenth)

Answer: B. 3.2
6 0
2 years ago
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A cube of sides 10cm was cut across to obtain a prism. Calculate the surface area of the prism and the volume of the prism
hodyreva [135]

Answer:

Part A

The volume of the triangular prism is 500 cm³

Part B

The total surface area of the prism is approximately 441.42 cm²

Step-by-step explanation:

The given details are;

The dimensions of the side length of the cube, s = 10 cm

The shape the cube was cut across to obtain = A prism

Part A

Whereby the prism obtained is a triangular prism, we have;

The cube can be cut in half to form a triangular prism

The volume of each triangular prism obtained = (1/2) × The volume of the cube

∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³

Part B

The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism

The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50

The square cross sectional area, A₂  = 10 × 10 = 100

The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2

The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃

∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42

The total surface area of the prism, A ≈ 441.42 cm²

4 0
3 years ago
What is the formula for midpoint?
kiruha [24]

Answer:

(x1 + x2 ÷ 2), (y1 + y2 ÷ 2)

4 0
3 years ago
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