A hypothetical square grows so that the length of its diagonals are increasing at a rate of 8m/min. How fast is the area of the
square increasing when the sides are 8m each.
2 answers:
Answer: The area of the square is increasing at a rate of 90.4 m2/min (square meters/minute)
Step-by-step explanation: Please see the attachments below
Answer:
The area of the square is increasing at 90.51m^2/min
Step by step explanation:
Given;
Change in diagonal length ∆d = 8m/min
Length l = 8m
When l = 8m
d^2 = 2l^2 = 2×8^2 = 128
d = √128
Area of a square = l^2 = (d^2)/2
d = diagonal
Change in area = ∆A = dA/dd
∆A = 2 × d/2 × ∆d = d×∆d
∆A = √128 × 8 = 90.51m^2/min
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