<span>1. take English and niether of the other two?
</span>36-6 that we know take all 3
This leave 30.
Subtract the 6 from those taking history and English. Leaves 10.
Subtract the 10 from those taking English.
This leaves 20.
Subtract the 6 from those taking political science and English. Leaves 8.
Subtract 8 from those taking English.
Leaves 12
<span>
2. take none of the three courses? </span>
<span>
3. take history, but niether of the other two
</span>Do the same with history as we did with English.
32-6 = 26 -10=16-10=6
<span>
4. take political science and history but not english
</span>16-6 (that take all 3) = 10
Hope at least the partial answer helps!
Answer:
thank you still mad
Step-by-step explanation:
Answer:
7/7
Step-by-step explanation:
The fraction 7/7 is considered to be improper by most mathematicians. The definition of a proper fraction is that the numerator is less than the
Answer:
Step-by-step explanation:
Given that,
f(x, y) = xe^−x(1 + y) x ≥ 0 and y ≥ 0
It is f(x, y)= 0 otherwise
To find probability of life time, we will take the double integral of the function with respect to X and Y
Y ranges from 0 to ∞
X exceed 5, so it ranges from 5 to ∞
∫ ∫ f(x, y) dxdy
∫ ∫ xe^−x(1 + y) dxdy
∫ ∫ x•e^(−x -xy) dxdy
Separating the exponential
∫ ∫ x•e^(−x) • e^(-xy) dxdy
Integrating with respect to y and keeping x as a constant.
∫ x•e^(−x) • e^(-xy) / -x dx
∫ - e^(−x) • e^(-xy) dx y = 0 to y=∞
∫ - e^(−x) • [e^(-∞) - e^(0) ]dx
∫ - e^(−x) • [ 0 - 1] dx
∫ - e^(−x) • -1 dx
∫ e^(−x) dx
Now integrating this
e^(-x) /-1 from x=5 to x=∞
-e^(-x) from x=5 to x=∞
- [ e^(-∞) - e^(-5)]
- (0-e^(-5))
- - e^(-5)
e^(-5) = 0.006738
To 3d.p =0.007
Then probability that the life time X exceed 5 is 0.007
