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dsp73
3 years ago
15

Choose the correct simplification and demonstration of the closure property given: (2x3 + x2 − 4x) − (9x3 − 3x2).

Mathematics
1 answer:
Leni [432]3 years ago
3 0

Answer:

B)

Step-by-step explanation:

(2x^3+x^2-4x)-(9x^3-3x^2)

2x^3-9x^3+x^2-(-3x^2)-4x

-7x^3+x^2+3x^2-4x

-7x^3+4x^2-4x

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Simplify the following expressions by using the order of operations
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11. 6 + 5 * 2 + (-3)
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      67 + 84 - 48/16
      67 + 84 - 3
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13. -5 * -6 - 25/5 - 2
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14. 18 - (9 + 3) + 2^3
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15. -24 / -6 * 2
       4 * 2
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16. 8 [ (26 + 10) - 4(3 + 2)]
      8 [ (36 - 4(5)]
      8 [ 36 - 20 ]
      8 [ 16 ]
        128 <==

17. 6 * 3 / 9 * 2 + 1
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18. (9 - -4)(-8 - -7)
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5 0
3 years ago
How do you write 11,000 in Japanese (in kanji)
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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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Answer:

Step-by-step explanation:

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6 0
2 years ago
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
3 years ago
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