I have no idea how to help you srry . . . . .
Answer:
Second point (-5/2, -7/2)
First point (3/2, 17/2)
Step-by-step explanation:
We have two equations, and we want to know at wich poin are equal. Hence, we have a system of equations and the solution is nothing more that the point (x,y) where those functions intercepts.
4x2+ 7x -11=y
3x+4=y
Lets use substitute method
4x2+7x-11=3x+4
This can be re arrange as the following eq:
4x2+4x-15=0
A quadratic equation, its solution can be obtained using the below eq.

where a=4, b=4, c=-15.
Remember, the quadratic equation as a +/- sign, meaning that you will obtain one answer using the + operator and other using the - operator.
By doing the above, we have x=-5/2 and x=3/2
By using x=3/2 in equation of line (3x+4=y) we have y=17/2
First point (3/2, 17/2)
By using x=-5/2 in equation of line (3x+4=y) we have y= -7/2
Second point (-5/2, -7/2)
Those points are the ones where the line and the parabola intercept.
I think it’s false
Correct me if I’m wrong
Hello :
an equation of the circle <span>Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -2 and b =-3 (</span><span>Center A(-2,-3))
r = AP......(P(-2,0))
r² = (AP)²
r² = (-2+2)² +(-3-0)² = 9
</span><span>an equation of the circle that satisfies the stated conditions.
Center </span> A(-2,-3) , passing through P(-2, 0) is : (x+2)² +(y+3)² = 9