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3 years ago

HELP!!!!

2 answers:

8 0

A: (5(6))/(3(-4)+(6)) = -5
B: 2(6)^2-(-4)^3 = 136

Substitute the value given as x and y into your expression. For A. , order of operation matters. I assumed the “+x” is part of the denominator.

Law Incorporation [45]3 years ago

5 0

Answer:

A. 5x/3y+x=5×6/(3×-4)=30/-12=-10/4=-5/2

B. 2x (square) - y (cube)=2×6²-(-4)³=72--64=72+64=136

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The length of time for one individual to be served at a cafeteria is a random variable having an exponential distribution with a

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$P(Y \geq 5)= 0.0729+0.0158+0.00146=0.0902$

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Solution to the problem

Let Y the random variable that represent the lenght of time for one individual to be served at the cafeteria. We know from the probalem that $Y\sim exp(\mu=4)$

On this case the probability density function would be given by:

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And 0 for other case. In order to solve this problem we need to fidn first the probability that a person would be served in less than 2 minutes. And in order to find it we need to find the cumulative distribution function integrating the density function like this:

$P(Y \leq 2) = \int_{0}^3 f(y) dy$

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And with this probability we can find the probability that a person would be served in less than 2 minutes on at least 5 of the next 7 days.

And on this case we can use the binomial distribution, and we want this probability:

$P(Y \geq 5)= P(Y=5) +P(Y=6) +P(Y=7)$

We can find the individual probabilities like this:

$P(Y=5)=(7C5)(0.3935)^5 (1-0.3935)^{7-5}=0.0729$

$P(Y=6)=(7C6)(0.3935)^6 (1-0.3935)^{7-6}=0.0158$

$P(Y=7)=(7C7)(0.3935)^7 (1-0.3935)^{7-7}=0.00146$

$P(Y \geq 5)= 0.0729+0.0158+0.00146=0.0902$

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