<h3>
Answer: n = -11</h3>
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Explanation:
Since x-2 is a factor of f(x), this means f(2) = 0.
More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.
So if we plugged x = 2 into f(x), we'd get
f(x) = x^3+x^2+nx+10
f(2) = 2^3+2^2+n(2)+10
f(2) = 8+4+2n+10
f(2) = 2n+22
Set this equal to 0 and solve for n
2n+22 = 0
2n = -22
n = -22/2
n = -11 is the answer
Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10
Plug x = 2 into that updated f(x) function to find....
f(x) = x^3+x^2-11x+10
f(2) = 2^3+2^2-11(2)+10
f(2) = 8+4-22+10
f(2) = 0
Which confirms our answer.
Answer: x=6
The two angles shown in each are complementary because they add up to 90°.
10 & 12 would be supplementary to one another because they would add up to 180°.
Step-by-step explanation:
We know that on both 10 & 12 the angles add up to equal 90° so...
10. 8x+7x=90
15x=90
x=6
12. it's the same in pic as 10
The two angles shown in each are complementary because they add up to 90°.
10 & 12 would be supplementary to one another because they would add up to 180°.
This is a normal distribution with a Mean: 14 g/dL and a Standard deviation: 1 g/dL.
A ) Hemoglobin levels less than 13:
13 = 14 - 1 = Mean - 1 SD
0.16 x 200 = 32
Answer: 32 people.
B ) Hemoglobin levels greater than 14 :
0.50 x 200 = 100
Answer: 100 people.
You can round 15 to 20, and 8 to 10
The option are missing in the question. The options are :
A. P = 2, a = 1
B. 
C. 
D. P = 2, a = 3
Solution :
The given function is 
So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.
When the four option being substituted in the function, we get
A). It is a constant function since 
B). Here, the value of a is a fraction which is less than 1, so it is a decay function. 
C). It is a constant function since the value of a is 1.
D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

Therefore, option (D). represents an exponential function.