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2 years ago

Cot^2(alpha)csc(alpha)+2cot(alpha)csc(alpha)-3csc(alpha)

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

cot²α csc α+2 cot α csc α-3 csc α

=csc α (cot²α+2cot α-3)

=csc α (cot² α+3cot α- cot α-3)

=csc α[cot α(cot α+3)-1(cot α+3)]

=csc α (cot α+3)(cot α-1)

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2 years ago

What is the surface area of this triangular prism? The base of each triangle is 42 m and the height of the triangular base is 20

shutvik [7]

Given:

The base of each triangular base is 42 m.

The height of each triangular base is 20 m.

The sides of the triangle are 29 m each.

The height of the triangular prism is 16 m.

We need to determine the surface area of the triangular prism.

Surface area of the triangular prism:

The surface area of the triangular prism can be determined using the formula,

$SA=bh+(s_1+s_2+s_3)H$

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Substituting the values, we get;

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2 years ago

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2 years ago

What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?

Aleonysh [2.5K]

Answer:

$\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).$

$\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}$

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3 years ago

Read 2 more answers

8+2(5 - x) = Need help

nikdorinn [45]

We can distribute
2(5)+2(-x)=10-2x

we get
8+10-2x=?
18-2x=?

whatever that ? is, we don't know
multiply both sides by -1
2x-18=-?
add 18 to both sides
2x=18-?
divide bth sides by 2
x=9-(?/2)
whatever the left side it, just divide it by 2 and subtract it from 9

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3 years ago