2 years ago

Cot^2(alpha)csc(alpha)+2cot(alpha)csc(alpha)-3csc(alpha)

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

4 0

Answer:

Step-by-step explanation:

cot²α csc α+2 cot α csc α-3 csc α

=csc α (cot²α+2cot α-3)

=csc α (cot² α+3cot α- cot α-3)

=csc α[cot α(cot α+3)-1(cot α+3)]

=csc α (cot α+3)(cot α-1)

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