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2 years ago

PLEASE HELP WILL GIVE BRAINLIEST AND LOTS OF POINTS

Mathematics

2 answers:

Ad libitum [116K]2 years ago

6 0

4,3,2,1 they all go in order hope you have a wonderfully day msg me if you have any questions ok?

Tasya [4]2 years ago

3 0

The tiles go in this order: 4,3,2,1

Hope this helps!

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Cost to store 155 mark up 30

pickupchik [31]

Answer:

201.50

Step-by-step explanation:

SP = CP + markup

155 + 30% =
155*1.3 =
201.50

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2 years ago

Mr. Mutler posts his students' artwork on a bulletin board.

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The length could be 5 and width 3. That would equal 15

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2 years ago

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stealth61 [152]

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2 years ago

Can you find the rate of change for the following function: -6x + 3y =9?

IgorC [24]

Answer:

The general rate of change can be found by using the difference quotient formula. To find the average rate of change over an interval, enter a function with an interval:

f ( x ) = x ^2 , [ 2 , 3 ]

The rate of Change is 2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

2 years ago