Question

Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid. What is the distance, in units, between the points Ralph plotted?
Enter your numerical answer in the box, do not include words or spaces.

Answer 1

Answer:

6 units

Step-by-step explanation:

Given the following question:

Point A = (-4, 3) = (x, y)
Point B = (-4, -3) = (x, y)

To find the distance between the following points we must first plot the points on the coordinate plane.

Point A: Move over to the left four times, move up three times.
Point B: Move over to the left four times, move down three times.

The distance between the two points given is "six units." Since the x values are the same, and the y values are opposites from each other doubling their distance by two.

Hope this helps.

Answer 2

DISTANCE

❖ Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid. What is the distance, in units, between the points Ralph plotted? (Enter your numerical answer in the box, do not include words or spaces.)

Answer:

• $\color{hotpink} \bold{6 \: units}$

— — — — — — — — — —

Formula:

- To get the distance between two points, we may use formula

• $\underline{ \boxed{d = \sqrt{( x_{2} - x_{1}) {}^{2} + (y_{2} - y_{1}) {}^{2} } }}$

Given:

Since Ralph plotted the points (-4, 3) and (-4, -3) on a coordinate grid then, the givens are...

• $\: \: \: \: \: \: \: x_{1} = - 4 \: \: \: \: \:\: \: \: \: \: \: \: \: y_{1} = 3\\ \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: y_{2} = - 3$

Solution:

• $d = \sqrt{( x_2- x_{1}) {}^{2} + (y_{2} - y_{1}) {}^{2} }$

• $d = \sqrt{[-4-(-4)]²+(-3-3)²}$

• $d = \sqrt{(0)²+(-6)²}$

• $d = \sqrt{0+36}$

• $d = \sqrt{36}$

• $d = \blue{6}$

Therefore, the distance between two given points is 6.