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3 years ago

Please help me out in optional maths

Mathematics

1 answer:

antoniya [11.8K]3 years ago

3 0

WHAT THE OTHER PERSON SAID

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Find the solution set for the following equation. <img src="https://tex.z-dn.net/?f=-%5Csqrt%28x%29%3D5" id="TexFormula1" title=

andrey2020 [161]

Answer:

Solution set = {25}

Step-by-step explanation:

=> $-\sqrt{x} =5$

Dividing both sides by -1

=> $\sqrt{x} = -5$

Taking square on both sides

=> x = 25

<em><u>Solution set = {25}</u></em>

3 0

2 years ago

Three people invest in a treasure dive, each investing the amount listed below. The dive results in 40 gold coins. Apportion tho

garri49 [273]

Answer:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

Step-by-step explanation:

We know that the dive results in 40 gold coins.

We know that:

Alice: $7,600 Ben: $5,900 Carlos: $1,400.

So they have $ 14900 in total.

Now we will divide that money by 40.

$x=\frac{14900}{40}\\\\x=372.5$

So 1 gold coin costs $ 372.5. Now we will calculate how much they can get for the money they have.

$A=\frac{7600}{372.5}=20.4\\\\B=\frac{5900}{372.5}=15.8\\\\C=\frac{1400}{372.5}=3.75\\$

We conclude that:

Alice: 20 coins, Ben: 16 coins, and Carlos: 4 coins.

6 0

2 years ago

A. True

MrRissso [65]

The answer would be false

8 0

2 years ago

Find the minimum, maximum, and range for the given set of data.

serg [7]

The answer is option C

7 0

2 years ago

Read 2 more answers

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

AlexFokin [52]

Answer:

The standard form of quadratic equation is $x^2-16x-36=0$

The factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

Step-by-step explanation:

Given equation $x^2-6=16x+30$

We have to write in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as $ax^2+bx+c=0$

Consider $x^2-6=16x+30$

Taking all terms to left side, we have,

$x^2-6-16x-30=0$

Adding like terms, we have,

$x^2-16x-36=0$

Now we will factorize it.

We will solve the quadratic equation $x^2-16x-36=0$ using middle term splitting method,

-16x can be written as -18x+2x

$x^2-16x-36=0$ becomes

$\Rightarrow x^2-18x+2x-36=0$

Taking x common from first two terms and 2 common from last two terms we have,

$\Rightarrow x(x-18)+2(x-18)=0$

$\Rightarrow (x+2)(x-18)=0$

Thus, the factored form of $x^2-16x-36=0$ is $(x+2)(x-18)=0$

4 0

2 years ago

Read 2 more answers

Please help me out in optional maths​

Please help me out in optional maths