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3 years ago

X^2+3x+2 x^2+x-6 x^2-x-2

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Answer:

1. (+1)(+2)

2. (−2)(+3)

3. (−2)(+1)

Step-by-step explanation:

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Similar figures have the same

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Answer:

Similar figures have the same shape, but not the same size.

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3 years ago

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According to a recent government report, the aging of the U.S. population is translating into many more visits to doctors' offic

olga_2 [115]

Answer:

0.2835 = 28.35% probability that an average person makes at least one MONTHLY visit to doctors' office and hospitals

Step-by-step explanation:

Mean during a time period means that we use the Poisson distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

It is estimated that an average person makes four visits a year to doctors' offices and hospitals.

A year has 12 months, which means that the monthly mean is $\mu = \frac{4}{12} = \frac{1}{3}$

What is the probability that an average person makes at least one MONTHLY visit to doctors' office and hospitals?

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-(\frac{1}{3})}*(\frac{1}{3})^{0}}{(0)!} = 0.7165$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7165 = 0.2835$

0.2835 = 28.35% probability that an average person makes at least one MONTHLY visit to doctors' office and hospitals

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3 years ago

A cubic centimeter holds 1 milliliter of liquid. How many liters of water to the nearest tenth are required to fill a fish tank

Nady [450]

The answer is 24.192. You multiply the length and width and height to get the volume in milliliters, then divide by 1000 to get the volume in liters

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3 years ago

a line represented by y = 5x − 2 and a line perpendicular to it intersect at r(1, 3). what is the equation of the perpendicular

Snezhnost [94]

Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1

So a tangent of the perpendicular line is "-(1/5)".

Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).

On the other hand, this equation pass r(1, 3), so

3 = -(1/5) times 1 + a

∴ a=16 / 5

Therefore, y=-(1/5)x+16 /5 is answer.

By the way, I'm Japanese so if you find some mistakes in my English, please let me know.

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4 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

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3 years ago