X^2+3x+2 x^2+x-6 x^2-x-2
1 answer:
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Hello!
Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards
15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333
Multiply these to find the volume
5 * 5 * 0.08333 = 2.08325
Multiply this by the cost
2.08325 * 46 = 95.83
The answer is C) $95.83
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Question 2
You have to find the volume of the first pyramid
The equation we use is
V is volume
l is length
w is width
h is height
Put in the values we know
Multiply
Divide
V = 2389.3333
Now we use this to find the side length of the second pyramid
Multiply both sides by 3
<span>7167.999 = lw * 112
</span>
Divide both sides by 112
63.9999 = lw
Since it is a square pyramid we know that sides are equal
63.999 = l^2
Take the square root of both sides
8 = l
The answer is B) 8in
Hope this helps!
Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards
15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333
Multiply these to find the volume
5 * 5 * 0.08333 = 2.08325
Multiply this by the cost
2.08325 * 46 = 95.83
The answer is C) $95.83
------------------------------------------------------------------------------------------------------
Question 2
You have to find the volume of the first pyramid
The equation we use is
V is volume
l is length
w is width
h is height
Put in the values we know
Multiply
Divide
V = 2389.3333
Now we use this to find the side length of the second pyramid
Multiply both sides by 3
<span>7167.999 = lw * 112
</span>
Divide both sides by 112
63.9999 = lw
Since it is a square pyramid we know that sides are equal
63.999 = l^2
Take the square root of both sides
8 = l
The answer is B) 8in
Hope this helps!