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3 years ago

Write a linear equation that goes through the points (-1,-10) and (5,2).

Mathematics

1 answer:

Degger [83]3 years ago

7 0

Answer:

y = 2x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 1, - 10) and (x₂, y₂ ) = (5, 2)

m = $\frac{2-(-10)}{5-(-1)}$ = $\frac{2+10}{5+1}$ = $\frac{12}{6}$ = 2 , then

y = 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (5, 2 ) , then

2 = 10 + c ⇒ c = 2 - 10 = - 8

y = 2x - 8 ← equation of line

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If PQRS is a kite, find m angle Q

balu736 [363]

Answer:

m<Q = 78°

Step-by-step explanation:

First, find the value of x:

7x + 2 = 10x - 31 (Non-vertex angles of a kite are congruent to each other)

Collect like terms

7x - 10x = -2 - 31

-3x = -33

Divide both sides by -3

x = 11

Find m<Q:

Sum of all angles in a kite = 360°

Therefore,

m<Q + m<P + m<S + m<R = 360°

m<Q + (7x + 2) + 124 + (10x - 31) = 360

Plug in the value of x

m<Q + (7*11 + 2) + 124 + (10*11 - 31) = 360

m<Q + 79 + 124 + 79 = 360

m<Q + 282 = 360

Subtract 282 from both sides

m<Q + 282 - 282 = 360 - 282

m<Q = 78°

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3 years ago

Dr black is standing 20 feet from street lamp lamp shadow is 5 feet long angle from top of his shadown to top of light is 30degr

s344n2d4d5 [400]

Then answer would be

90° < 0 < 180°.

hope it helps!

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4 years ago

Arthur walked 6 kilometers around the park, and D.W. sprinted 200 m at the park. How many meters did they travel in total?

nevsk [136]

Answer:

6200 meters

Step-by-step explanation:

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3 years ago

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4vir4ik [10]

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kirill115 [55]

Looks like

$\vec F(x,y,z)=y\,\vec\imath+z\,\vec\jmath+xz\,\vec k$

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By the divergence theorem,

$\displaystyle\iint_{\partial R}\vec F\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F\,\mathrm dV$

The divergence is

$\mathrm{div}\vec F(x,y,z)=(y)_x+(z)_y+(xz)_z=x$

so that the surface integral reduces to

$\displaystyle\iiint_Rx\,\mathrm dV$

or in cylindrical coordinates,

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3 years ago