Answer: (6x^4 - 15x^3 - 2x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 - 15x^3 + 4x^2 - 6x^2 - 10x - 4) ÷ (3x^2 + 2)
= (6x^4 + 4x^2 - 15x^3 - 10x - 6x^2 - 4) ÷ (3x^2 + 2)
= 2x^2(3x^2 + 2) - 5x(3x^2 + 2) - 2(3x^2 + 2) ÷ (3x^2 + 2)
= (3x^2 + 2)(2x^2 - 5x - 2) ÷ (3x^2 + 2)
= 2x^2 - 5x - 2 Ans.
I hope this helped!!! NO HATE COMMENTS IF I WAS WRONG!!!
Answer:
Step-by-step explanation:
Given the inequality
|x|> 1
The modulus of x shows that x can be both positive and negative value.
If x is positive:
x>1
1<x
If x is negative:
-x>1
Multiplying both sides of the inequality by minus will change the inequality sign
x < -1
Combining both inequalities:
1<x<-1
Find the position on the number line in the attachment
Answer:
let x adult and y student attended
x+y= 94
x=94-y
again
4x+2y = 294 53 adults and 41 student attended
376-4y+2y =294 the event
2y =82
y=41
substituting the value of y in
x+y =94
x= 94-41 = 53
Step-by-step explanation:
Answer:
x > -7/17
Step-by-step explanation:
You first divide -7 by 17 to isolate the variable, (x).
And thats it!
