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tamaranim1 [39]
3 years ago
7

Hope this makes you day

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

a

Step-by-step explanation:

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I NEED HELP !!!!!!!!!!!!!!!!!!!!!
cricket20 [7]

you must substitute x in the equation given :)

examples:

when x is -2

therefore, y = 2(-2) + 3

y = -1

when x is 0

therefore, y = 2(0) + 3

y = 3

when x is 1

therefore, y = 2(1) + 3

y = 5

when x is 3

therefore, y = 2(3) + 3

y = 9

for (b) you only have to plot based on the table ;)

hope this helps

8 0
3 years ago
Which basic trigonometric identity would you use to verify that tan x cos x =sin x
True [87]

Answer:

\huge\boxed{\tan x=\dfrac{\sin x}{\cos x}}

Step-by-step explanation:

\tan x\cos x=\sin x\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\text{Therefore}\\\\\tan x\cos x=\dfrac{\sin x}{\cos x}\cdot\cos x\qquad\text{cancel}\ \cos x\\\\\tan x\cos x=\sin x\\\\\text{For}\ x\neq\dfrac{\pi}{2}+k\pi},\ k\in\mathbb{Z}

7 0
3 years ago
The basket of golf balls at a miniature golf course contains 18 golf balls, of which 9 are red. What is the probability that a r
alexira [117]
It will be 2 because 19/9 is 2
5 0
3 years ago
Read 2 more answers
A grocery store sells 6 bottles of water for $4.00 ad 15 bottles of water for $10.00. Is the cost of the water proportional to t
barxatty [35]
Yes, the cost is proportional to the number of water bottles sold. 6 water bottles/$4.00 = 1.5 and 15 water bottles/$10.00 = 1.5.
7 0
3 years ago
Help please!! How do I solve this
egoroff_w [7]
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
 2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0  We will replace expression ( 2 on x) with variable t => 2 on x=t  =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 =>     t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 =>                   2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution. 
Check 2:   2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 => 
1-5+4=0 => 0=0  Identity provin solution.
5 0
3 years ago
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