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Alona [7]
3 years ago
14

An arc of a circle of radius 7cm subtends an eagle of 120degree at the centre. Find its perimeter.

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

\dfrac{14\pi }{3}\ cm

Step-by-step explanation:

The circumference of the circle with radius of 7 cm is

C=2\pi r\\ \\C=2\pi \cdot 7=14\pi \ cm

An arc of a circle o subtends an angle of 120^{\circ} at the centre.

The circle has the full angle of 360^{\circ}, then

14\pi \ cm - 360^{\circ}\\ \\x\ cm - 120^{\circ}

Write a proportion:

\dfrac{14\pi }{x}=\dfrac{360}{120}\\ \\\dfrac{14\pi }{x}=\dfrac{3}{1}\\ \\14\pi =3x\\ \\x=\dfrac{14\pi }{3}\ cm

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satela [25.4K]
Convert the percentages in decimals:
90/100 = 0.9,  20/100 = 0.2

Multiply the decimals:
0.9 times 0.2 is 0.18, or 18%

Greg has an 18% chance of being elected both positions.



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3 years ago
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Angle WOM is congruent to angle ___. Why?
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Answer:

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Step-by-step explanation:

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Please answer this question! 32 points and brainliest!!
stepladder [879]

Answer:

3x^2 -7x +2

Step-by-step explanation:

(15x^2 -35x+10) ÷5

(15/5x^2 -35/5x+10/5)

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This will factor

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5 0
3 years ago
The American Bankers Association reported that, in a sample of 120 consumer purchases in France, 48 were made with cash, compare
tatuchka [14]

Answer:

Step-by-step explanation:

Hello!

You have the information for two variables

X₁: Number of consumer purchases in France that were made with cash, in a sample of 120.

n₁= 120 consumer purchases

x₁= 48 cash purchases

p'₁= 48/120= 0.4

X₂: Number of consumer purchases in the US that were made with cash, in a sample of 55.

n₂= 55 consumer purchases

x₂= 24 cash purchases

p'₂= 24/55= 0.4364

You need to construct a 90% CI for the difference of proportions p₁-p₂

Using the central limit theorem you can approximate the distribution of both sample proportions p'₁ and p'₂ to normal, so the statistic to use to estimate the difference of proportions is an approximate standard normal:

[(p'₁-p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }]

Z_{0.95}= 1.648

[(0.4-0.4364)±1.648 * \sqrt{\frac{0.4(1-0.4)}{120} +\frac{0.4364(1-0.4364)}{55} }]

[-0.1689;0.0961]

The interval has a negative bond, it is ok, keep in mind that even tough proportions take values between 0 and 1, in this case, the confidence interval estimates the difference between the two proportions. It is valid for one of the bonds or the two bonds of the CI for the difference between population proportions to be negative.

I hope this helps!

8 0
3 years ago
Can someone help me with all of these
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7. = 29/9 0.6 terminating
8. = 301/20 0.75 terminating

6 0
3 years ago
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