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3 years ago

PLEASE HELP!!!!!! I really need help on this! It's due today and I'm kinda late on it!!

Mathematics

1 answer:

Margaret [11]3 years ago

3 0

Answer:

1.not 2×4 is 2+4 answer should be 6x⁶

2.not 3+4 is 3×4 answer should be 12a⁷

3.miss 1 should x^(6+1+3) should be x¹⁰

4.base different, and just become 81×8=648

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I really need help please I will mark you as brainlist

Gelneren [198K]

15/2 = $7.5 per hour
7.5 times 5 = $37.50 earned in 5 hours

5 0

3 years ago

Read 2 more answers

What is the surface area of the box if it is scaled up by a factor of 10? Boxes Dimensions 7in Height 6in Length 2in Width

VladimirAG [237]

Answer:

13,600 $in^{2}$

Step-by-step explanation:

(h = 7, l = 6, w = 2) 10

70, 60, 20

2(h × w) + 2(h × l) + 2(w × l)

= 2(70 × 20) + 2(70 × 60) + 2(20 × 60)

= 2(1400) + 2(4200) + 2(1200)

= 2800 + 8400 + 2400

= 13,600

4 0

3 years ago

BRAINLIEST TO CORRECT QUICKLY

Pani-rosa [81]

Answer:

-6 3/8 < -7/8

Step-by-step explanation:

Answer:

-6 3/8 < -7/8

Showing Work

Using the given inputs:

-6 3/8 -7/8

Rewriting these inputs as improper fractions:

-51/8 and -7/8

Since we have like denominators we compare the inputs by the numerators:

Therefore, comparison shows:

-6 3/8 < -7/8

8 0

2 years ago

Read 2 more answers

Cesar, Carmen, and Dalila raised $95.34 for their tennis team. Carmen raised $12.12 less than Cesar, and Cesar raised $35 more t

NeTakaya

Answer:

Cesar's amount can be expressed by x + 12.12

Dalila's amount can be expressed as x - 22.88

Step-by-step explanation:

If Carmen raised 12.12.less than Cesar, that means his amount is 12.12 more than hers so that is x + 12.12 for Cesar.

If Cesar raised 35 more than Dalila, her amount is Cesar's minus 35. Calculate: x+12.12 - 35. the difference is 22.88 less than x so the amount for Dalila is x- 22.88

5 0

3 years ago

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

3 years ago