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nikklg [1K]
3 years ago
7

PLEASE HELP!!!!!! I really need help on this! It's due today and I'm kinda late on it!!

Mathematics
1 answer:
Margaret [11]3 years ago
3 0

Answer:

1.not 2×4 is 2+4 answer should be 6x⁶

2.not 3+4 is 3×4 answer should be 12a⁷

3.miss 1 should x^(6+1+3) should be x¹⁰

4.base different, and just become 81×8=648

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When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exp
marysya [2.9K]

Answer:

  -5 or 5 depending on how you write the simplified form

Step-by-step explanation:

\dfrac{27x^2z}{3x^2z^6}=9x^{2-2}z^{1-6}\\\\\boxed{=9z^{-5}=\dfrac{9}{z^5}}

__

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  1/a^b = a^-b

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Some folks like their simplified form to contain only positive exponents. Other folks avoid unnecessary fractions. Choose the form that satisfies your grader.

4 0
3 years ago
The <br> 180<br> falls between which two whole numbers?
dimulka [17.4K]
179 AND 181, THATS RIGHT BOIII
3 0
3 years ago
Read 2 more answers
Please help!!!? Find m
Maru [420]

Answer:

Step-by-step explanation:

m\angle F =tan^{-1}\frac{4}{6}\\m\angle F =33.690067526\degree\\m\angle F =33.7\degree

3 0
3 years ago
If A(3,4) and B(10,4) are the end points of a diameter of circle "O", what is the area of the circle O
ikadub [295]

Answer:

\large\boxed{\dfrac{49\pi}{4}}

Step-by-step explanation:

The formula of an area of a circle:

A=\pi r^2

<em>r</em> - radius

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d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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d=\sqrt{(10-3)^2+(4-4)^2}=\sqrt{7^2+0^2}=\sqrt{7^2}=7

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We know: <em>d = 2r.</em> Therefore

r=\dfrac{7}{2}

Substitute to the formula of an area:

A=\pi\left(\dfrac{7}{2}\right)^2=\dfrac{49\pi}{4}

<em>There is no such answer in the answers to choose.</em>

<em>Apparently you have some error in the coordinates of the endpoints.</em>

8 0
3 years ago
Solve each equation.<br>1. 9/2x+18+3x=11/2<br>2. (x+6)-(2x=7)-3x=-9
zzz [600]
1.\\\frac{9}{2}x+18+3x=\frac{11}{2}\ \ \ \ \ |Multiply\ by\ 2\\\\&#10;9x+36+6x=11\\\\&#10;15x+36=11\ \ \ |Subtract\ 36\\\\&#10;15x=-25\ \ \ |Divide\ by\ 15\\\\&#10;x=-1\frac{2}{5}\\\\&#10;2.\\&#10;(x+6)-(2x-7)-3x=-9\\\\&#10;x+6-2x+7-3x=-9\\\\&#10;-4x+13=-9\ \ \ |Subtract\ 13\\\\&#10;-4x=-22\ \ \ |Divide\ by\ -4\\\\&#10;x=5,5
3 0
3 years ago
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