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3 years ago

11

For what value of x does

id="TexFormula1" title="4^{x}=(\frac{1}{8})^{x + 5} " alt="4^{x}=(\frac{1}{8})^{x + 5} " align="absmiddle" class="latex-formula">
-15
-3
3
15

1 answer:

ss7ja [257]3 years ago

7 0

Write both sides as powers of 2:

$4^x=(2^2)^x=2^{2x}$

$\left(\dfrac18\right)^{x+5}=8^{-x-5}=(2^3)^{-x-5}=2^{-3x-15}$

Since both powers of 2 are equal, the exponents are equal:

2<em>x</em> = -3<em>x</em> - 15

5<em>x</em> = -15

<em>x</em> = -3

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Please help immediately! In desperate need!

grandymaker [24]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

You know that f(0) = 2^0 = 1, so g(0) = -11 has been shifted down 12 units from f(x). A shift of half as much will be a shift down 6 units from f(x), or up 6 units from g(x).

In the attached, we have named the new function h(x). It is equivalent to g(x)+6. That is, you can add 6 to each of the g(x) table values to get the corresponding values for h(x).

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3 years ago

The functions f(x) and g(x) are defined below.

madam [21]

Uh im not sure completely but ill try my best to help.

f(x)=x-16/(x+10)(x-4)
g(x)=1/x+10

Now find a common denominator. (x+10)(x-4) is a good one.

x-16/(x+10)(x-4)+x-4/(x+10)(x-4)
2x-20/(x+10)(x-4)

So I think the answer is 2(x-10)/(x+10)(x-4) and x≠-10 and x≠4

Thats the most you can factor it. Don’t try to cancel out the (x-10) and the (x+10)

Brainliest my answer if it helped you out?

5 0

3 years ago

Read 2 more answers

Find the lengths of the sides of the triangle PQR. P(2, −3, −4), Q(8, 0, 2), R(11, −6, −4) |PQ| = Incorrect: Your answer is inco

Aloiza [94]

Answer:

the length PQ is 9 units,the length QR is 9 units,the length PR is 9.48 units,the triangle is not a right triangle,this is a isosceles triangle

Step-by-step explanation:

Hello, I think I can help you with this

If you know two points, the distance between then its given by:

$P1(x_{1},y_{1},z_{1} ) \\P2(x_{2},y_{2},z_{2})\\\\d=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}+(z_{2}-z_{1} )^{2} }$

Step 1

use the formula to find the length PQ

Let

P1=P=P(2, −3, −4)

P2=Q=Q(8, 0, 2)

$d=\sqrt{(8-2)^{2} +(0-(-3))^{2}+(2-(-4))^{2}} \\ d=\sqrt{(6)^{2} +(3)^{2}+(6 )^{2}}} \\d=\sqrt{36+9+36}\\d=\sqrt{81} \\d=9\\$

the length PQ is 9 units

Step 2

use the formula to find the length QR

Let

P1=Q=Q(8, 0, 2)

P2=R= R(11, −6, −4)

$d=\sqrt{(11-8)^{2} +(6-0))^{2}+(-4-2 )^{2}} \\\\\\d=\sqrt{(3)^{2} +(6)^{2}+(-6 )^{2}}} \\d=\sqrt{9+36+36}\\d=\sqrt{81} \\d=9\\$

the length QR is 9 units

Step 3

use the formula to find the length PR

Let

P1=P(2, −3, −4)

P2=R= R(11, −6, −4)

$d=\sqrt{(11-2)^{2} +(-6-(-3)))^{2}+(-4-4 )^{2}} \\\\\\d=\sqrt{(9)^{2} +(-6+3)^{2}+(-4-(-4) )^{2}}} \\d=\sqrt{81+9+0}\\d=\sqrt{90} \\d=9.48\\$

the length PR is 9.48 units

Step 4

is it a right triangle?

you can check this by using:

$side^{2} +side^{2}=hypotenuse ^{2}$

Let

side 1=side 2= 9

hypotenuse = 9.48

Put the values into the equation

$9^{2} +9^{2} =9.48^{2}\\ 81+81=90\\162=90,false$

Hence, the triangle is not a right triangle

Step 5

is it an isosceles triangle?

In geometry, an isosceles triangle is a type of triangle that has two sides of equal length.

Now side PQ=QR, so this is a isosceles triangle

Have a great day

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What is the square root of 5<br>

Katen [24]

Answer:

2.24 (shortened) or

2.2360679775

Step-by-step explanation:

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