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adoni [48]
3 years ago
11

For what value of x does

id="TexFormula1" title="4^{x}=(\frac{1}{8})^{x + 5} " alt="4^{x}=(\frac{1}{8})^{x + 5} " align="absmiddle" class="latex-formula">
-15
-3
3
15​
Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

Write both sides as powers of 2:

4^x=(2^2)^x=2^{2x}

\left(\dfrac18\right)^{x+5}=8^{-x-5}=(2^3)^{-x-5}=2^{-3x-15}

Since both powers of 2 are equal, the exponents are equal:

2<em>x</em> = -3<em>x</em> - 15

5<em>x</em> = -15

<em>x</em> = -3

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