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2 years ago

Simplify 6-12b divided by 3a-6ab

Mathematics

2 answers:

siniylev [52]2 years ago

7 0

Answer:

$\frac{2}{a}$

Step-by-step explanation:

Given

$\frac{6-12b}{3a-6ab}$ ← factor both numerator and denominator

= $\frac{6(1-2b)}{3a(1-2b)}$ ← cancel common factor (1 - 2b) on numerator/denominator

= $\frac{6}{3a}$ ← cancel 6 and 3 by 3

= $\frac{2}{a}$

tigry1 [53]2 years ago

6 0

6-12b divided by 3a-6ab is equal to 2\a

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Answer:

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Anna11 [10]

Answer:

<h2>see below</h2>

Step-by-step explanation:

<h3>Question-6:</h3>

we are given a equation

$\sf \displaystyle \: \log_{4}( - x) + \log_{4}( 6 - x) = 2$

to solve so

recall logarithm multiplication law:

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cancel out $\log_4$ from both sides:

$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

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move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

$\sf \displaystyle \: - 6 x + {x}^{2} - 16 = 0$

rewrite it to standard form i.e ax²+bx+c=0

$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

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$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

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$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

group:

$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

$\displaystyle \: x = 8 \\ x = - 2$

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move left hand side log to right hand side:

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use mutilation logarithm rule;

$\displaystyle \: \log( {x}^{2} - 21x) = 2$

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make it standard form:

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factor:

$\displaystyle \: {(x} + 4)(x - 25)= 0$

$\displaystyle \: x = 25$

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