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Mashcka [7]
3 years ago
10

Solve the word problem.

Mathematics
1 answer:
finlep [7]3 years ago
7 0

Answer:

Ron: 6+2√5 days ≈ 10.47 days

Lee: 2+2√5 days ≈ 6.47 days

Step-by-step explanation:

Let L represent the number of days it takes Lee to frame a cabin. Then it take L+4 days for Ron to frame it. Working together, they take 4 days. Then their rates, in cabins per day, add up as ...

1/L + 1/(L+4) = 1/4

Multiplying by the product of denominators, we get ...

4(L+4) +4L = L(L+4)

Subtracting the left side gives ...

L^2 -4L -16 = 0

Completing the square, we can write this as ...

L^2 -4L +4 = 20

(L -2)^2 = 20

L = 2 + √20 = 2 +2√5 ≈ 6.47

Lee takes 2+2√5 ≈ 6.47 days to frame a cabin.

Ron takes 6+2√5 ≈ 10.47 days to frame a cabin.

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AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

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3 years ago
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i’m pretty sure the answer would be 1) linear :D
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