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ollegr [7]
3 years ago
9

-ive

Mathematics
1 answer:
monitta3 years ago
5 0

Answer:

1. The total number of students in the 25-34 age group

2. 2124/19558*100= 10.9 %

Step-by-step explanation:

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Evaluate the expression when a= 2 and c=-4.<br> -a +5c
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The answer would be 18
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Write the point-slope form of the equation of the line through the given point woth the given slope
Andrej [43]

Answer:

3.) \displaystyle y - 4 = 4[x - 1]

2.) \displaystyle y + 5 = 2[x + 2]

1.) \displaystyle y + 3 = 1\frac{1}{5}[x + 5]

Step-by-step explanation:

In the Point-Slope Formula, \displaystyle y - y_1 = m[x - x_1],all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

* \displaystyle 1\frac{1}{5} = \frac{6}{5}

I am joyous to assist you anytime.

3 0
3 years ago
2.<br> what do i put im confused and dont know how to do this
Paha777 [63]

Answer:

Step-by-step explanation:

The two dots on the bottom of this figure define the base of a triangle.  If we now use a compass to draw the blue arcs on either side, as shown, the arcs will intersect at two points.  A straight line drawn through these two points will be perpendicular to the base. The triangle will be isosceles and could be (but doesn't have to be) equilateral.

3 0
3 years ago
Please answer I need help quick!!!
grigory [225]

Answer:

85

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

8 0
3 years ago
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