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2 years ago

Find the angles ∠1 = ° ∠2 = ° ∠3 = °

Mathematics

1 answer:

ioda2 years ago

3 0

Angle 1 is 45 degrees
Angle 2 is 45 degrees
Angle 3 is 235 degrees

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twice the sum of a number and 2 is equal to three times the difference of the number and 8. Find the number.

Leto [7]

Answer: x = -22

Step-by-step explanation:

Look at picture!

4 0

3 years ago

Can someone help meee please

hoa [83]

Answer:

Equation → 5y = 3y + 6

Value of ST = 15

Step-by-step explanation:

From the picture attached,

In right triangles ΔVST and ΔVUT,

Acute angles ∠SVT ≅ ∠UVT [Given]

TV ≅ TV [By reflexive property of congruence]

ΔVST ≅ ΔVUT [Hypotenuse angle congruence of right triangles]

Therefore, corresponding parts of the congruent triangles are congruent.

Therefore, ST ≅ TU

5y = 3y + 6

5y - 3y = 6

2y = 6

y = 3

Therefore, ST = 5y

ST = 5(3)

= 15

8 0

2 years ago

Find the length of the hypotenuse in the triangle with a right side of 5 and a left side of 6. Which choice BEST describes the s

Helga [31]

Answer:

D irrational number

Step-by-step explanation:

because you do the Pythagorean theorem and you get 7.81024976 and that is a irrational number

6 0

3 years ago

Marco Drew 20 pictures he drew 3/4 of them in art class how many pictures did Marco draw in the art class.

Zielflug [23.3K]

He drew 15 in the art class.

6 0

3 years ago

Read 2 more answers

Please help!

crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

4 0

3 years ago