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daser333 [38]
3 years ago
14

Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was t

hree eighths the size of the brand name. If the generic television set is 12 inches by 24 inches, what are the dimensions of the brand name television?
Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer:

<em>The brand name television's dimensions are 32 inches by 64 inches.</em>

Step-by-step explanation:

<u>Scaling</u>

Jason is considering two similar televisions at a local store. The sizes of the generic television are 3/8 the size of the brand name.

If we knew the size of the brand name television, we would have to multiply its dimensions by 3/8, but instead, we have the dimensions of the generic television, so to find the brand name television, we multiply by 8/3.

12 inches * 8/3 = 32 inches

24 inches* 8/3 = 64 inches

The brand name television's dimensions are 32 inches by 64 inches.

Rasek [7]3 years ago
4 0

Answer:

The brand name television's dimensions are 32 inches by 64 inches.

Step-by-step explanation:

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Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r
likoan [24]

The value of q(x) is 2 x+5

The value of r(x) is 6

Explanation:

The given expression is \frac{2 x^{2}+13 x+26}{x+4}

We need to rewrite the expression in the form of q(x)+\frac{r(x)}{b(x)}

Simplifying the expression, we get,

\frac{2 x^{2}+8 x+5x+26}{x+4}

Separating the fractions, we have,

\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}

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Now, we shall further simplify the term \frac{5 x+26}{x+4} , we get,

\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}

Common out 5 from the numerator, we have,

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q(x)=2 x+5

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