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horsena [70]
3 years ago
12

HELP PLEASE! Write and solve the equation: The squares are identical. What is the area of each square?

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0

If a=4:

HOW TO FIND THE AREA

<h2>A=4a (formula)</h2>

A=4*4

A=16

If it's 100:

A=4*100

A=400

Mashutka [201]3 years ago
5 0

Answer:

They are congruent, simple.

Step-by-step explanation:

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Identify the given trig ratio of an angle through the point (3, -2)
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Step-by-step explanation:

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3 years ago
Loren is flying round trip from Dallas, Texas, to Minneapolis, Minnesota. The fare for her ticket is $308. Each airport charges
KonstantinChe [14]

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Step-by-step explanation:

the fare : 308

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tax on fare : 12

total is : 308 + 32 + 12 = $352 <==

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2 years ago
In performing a chi-square goodness-of-fit test for a normal distribution, a researcher wants to make sure that all of the expec
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The degrees of freedom for the chi square statistic is 7-4=3

3 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST The frequency f​ (in waves per​ second) and the wavelength w​ (in meters) of a sound traveling
marshall27 [118]

You gave us the speed and the frequency, and you need the wavelength.

You were also nice enough to remind us that (fqy)x(lng) = speed.

So . . . F x W = 343 m/s

Divide each side by F :

W = (343 m/s) / F

W = (343 m/s) / (240 / s)

W = (343/240) m

<em>W = 1.429 meters</em>

8 0
3 years ago
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
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