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horsena [70]
3 years ago
12

HELP PLEASE! Write and solve the equation: The squares are identical. What is the area of each square?

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0

If a=4:

HOW TO FIND THE AREA

<h2>A=4a (formula)</h2>

A=4*4

A=16

If it's 100:

A=4*100

A=400

Mashutka [201]3 years ago
5 0

Answer:

They are congruent, simple.

Step-by-step explanation:

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Susan has a 12-inch board for constructing a wooden chair.The directions say to use a board that is 29 centimeters long.Id her b
Advocard [28]

We have been given that Susan has a 12-inch board for constructing a wooden chair.The directions say to use a board that is 29 centimeters long. We are asked to determine if Susan's board is long enough to cut or not.

We know that 1 inch is equal to 2.54 cm.

Let us convert 12 inches into cm by multiplying 12 by 2.54.

12\text{ inches}=12\times 2.54\text{ cm}

12\text{ inches}=30.48\text{ cm}

Since 12 inches is equal to 30.48 centimeters and 30.48 is greater than 29, therefore, Susan's board in long enough to cut.

6 0
3 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
Solve for y, show your steps<br><br><br>y = x(2y - 3)
Xelga [282]

Answer:

y=\frac{-3x}{-2x+1}

Step-by-step explanation:

3 0
3 years ago
Solve by using the perfect squares method.* x2 – 12x + 36 = 0
ElenaW [278]
x^2 -12x + 36 = 0\\ \\ (x-6)^2= 0 \\ \\ x-6=0 \\ \\ x=6
4 0
3 years ago
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Twenty-six , 2 tens 6 ones , 25, 20+6 which one is the odd one out?
Aneli [31]

Answer:

25

Step-by-step explanation:

twenty-six=26

2 tens 6 ones= 26

25=25

20+6=26

25 is the odd one out.

8 0
3 years ago
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