Answer:
<h3>5 seccs</h3>
Step-by-step explanation:
Given the modeled function of the height expressed as;
h(t)=-16t^2+64t+80
The ball hits the ground when h(t) = 0 (when the height is zero)
Substitute into the function and find t;
0 =-16t^2+64t+80
divide through by -16
0 = t²-4t-5
Factorize;
t²-4t-5 = 0
t²-5t+t-5 = 0
t(t-5)+1(t-5) = 0
(t+1)(t-5) = 0
t + 1 = 0 and t-5 = 0
t = -1 and t = 5
Time can't be negative
Hence it will take the ball 5secs before it hits the ground
let "my number" = x
Multiply x by 5: 5(x)
and add 13: + 13
your expression would look like:
5x + 13
hope this helps
Pretty much saying 5+ (x*10)_<-25
Answer:
3.5°
Step-by-step explanation:
Subtract 82 and 54, to find the total change in temperature, 28.
7:00 am and 3:00 pm are 8 hours apart, so divide 28 by 8.
Your answer should be D, 3.5° per hour.
