The three slices are each approximately 1/9 pound in weight, and, since 2/9 is less than 1/4, he can eat 2 whole slices and be okay. If he wants to eat partial slices, then he could eat 2 1/4 slices, as each slice weighs 4/36 pounds, so 2 slices would equal 8/36 pounds, leaving 1/36 pound left over in his diet, which is a quarter of the third slice.
2.25
Answer:
The perimeter of △HFM is 50.75 units
Step-by-step explanation:
<u><em>The correct picture of the question in the attached figure</em></u>
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
we have
△HFM∼△PST ----> given problem
step 1
Find the scale factor
Let
z ----> the scale factor

substitute the given values

step 2
Find the perimeter of triangle PST
Remember that the perimeter of a triangle is the sum of its three length sides

step 3
Find the perimeter of triangle HFM
we know that
If two figures are similar, then the ratio of its perimeters is equal to the scale factor
so
The perimeter of triangle HFM is equal to the perimeter of triangle PST multiplied by the scale factor
so

Answer:
Step-by-step explanation:
x + y = 7 + 2/8 = 58/8
x - y = 2 + 4/8 = 20/8
Add the equations together
2x = 78/8
x = 39/8
y = x - 20/8 = 19/8
x = 39/8 = 4⅞
y = 19/8 = 2⅜
Answer:
The family bought 2 bags of chips
Step-by-step explanation:
Let the number of chips bags be = x
The number of candy bars = twice as much as the number of bags of chip
The number of candy bars = 2x
The total cost spent is = $5.50
Therefore cost of all the chips bags + candy bars = 5.50
2x + x = 5.50
3x = 5.50
x = 
x = 1.83
x = 2 (approx)
Thus the number of chips is 2 and the candy bars is 2(2) = 4 bags
Using a t-distribution calculator, the p-value is of 0.052, hence the range that contains the p-value is an interval between a number less than 0.05 and a number greater than 0.05.
<h3>How to find the p-value of the t-distribution?</h3>
To find the p-value of the t-distribution, three information, which are the inputs on the calculator are needed:
- The number of degrees of freedom.
In this problem, we have that:
- The test statistic is of t = -1.788.
- The number of degrees of freedom is of 10.
- We are testing if the mean is less than a value, hence we have a left-tailed test.
Hence, using a calculator, it is found that the p-value is of 0.052, hence the range that contains the p-value is an interval between a number less than 0.05 and a number greater than 0.05.
More can be learned about the t-distribution at brainly.com/question/13873630
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