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2 years ago

13

In Las Vegas, Nevada, stores charge a 4.6% state sales tax and a 3.65% county sales tax. Yuki is purchasing a handbag priced at

$220 before tax. How much sales tax does Yuki pay for her handbag purchase?

1 answer:

zysi [14]2 years ago

4 0

Answer:

$18.15

Step-by-step explanation:

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A rectangle has a length of (x + 4) centimeters and a width of 12x centimeters. If the perimeter is 26 centimeters, what is the

mars1129 [50]

Width of rectangle is 8.4 cm

Step-by-step explanation:

Length of rectangle = x+4

Width of rectangle = 12x

Perimeter = 26 cm

We need to find width of rectangle.

The formula used is:

$Perimeter=2(length+width)$

Putting values and finding x first:

$Perimeter=2(length+width)$

$26=2(x+4+12x)$

$26=2(13x+4)$

$26=26x+8$

$26-8=26x$

$26x=18$

$x=\frac{18}{26}$

$x=0.7$

So, value of x is 0.7

Now width= 12x = 12(0.7)

=8.4 cm

So, width of rectangle is 8.4 cm.

Keywords: Perimeter of Rectangle

Learn more about perimeter of rectangle at:

#learnwithBrainly

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2 years ago

What is the Perimeter of 168

Alexeev081 [22]

Answer:

???

Step-by-step explanation:

Could I have the L&W please?

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2 years ago

What is the discounted price for a watch that is regularly $58.00 and 30% off?

lukranit [14]

Answer:

$40.60

Step-by-step explanation:

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2 years ago

in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)

Nimfa-mama [501]

Answer:

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

Step-by-step explanation:

Let $\vec u$ and $\vec a$ , from Linear Algebra we get that component of $\vec u$ parallel to $\vec a$ by using this formula:

$\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a$ (Eq. 1)

Where $\|\vec a\|$ is the norm of $\vec a$ , which is equal to $\|\vec a\| = \sqrt{\vec a\bullet \vec a}$ . (Eq. 2)

If we know that $\vec u =(2,1,1,2)$ and $\vec a=(4,-4,2,-2)$ , then we get that vector component of $\vec u$ parallel to $\vec a$ is:

$\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)$

$\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

Lastly, we find the vector component of $\vec u$ orthogonal to $\vec a$ by applying this vector sum identity:

$\vec u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a}$ (Eq. 3)

If we get that $\vec u =(2,1,1,2)$ and $\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$ , the vector component of $\vec u$ is:

$\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)$

$\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$

The component of $\vec u$ orthogonal to $\vec a$ is $\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)$ .

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2 years ago

Which of the following is the equation of a line that has a slope of -2 and passes through the

UkoKoshka [18]

Answer:

ehhehrjrh4h4hehejejru4u4u

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2 years ago