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juin [17]
2 years ago
15

Dan received image off a pair of dress shoes that originally cost $54.00 and 20% off a pair of tennis shoes that originally cost

$44.00. How much more did he pay for his dress shoes than for his tennis shoes, before taxes?
A$4.70
B$5.30
C$10.00
D:$13.50
Mathematics
1 answer:
Alexxx [7]2 years ago
4 0

Answer:

hey preston im watching ur 7thgrade butt

Step-by-step explanation:

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Several million lottery tickets are sold, and 21% of the tickets are held by men. Suppose you select a random sample of people a
valina [46]

Answer:

hypergeometric

Step-by-step explanation:

For each winning ticket, there are only two possible outcomes. Either it is held by a men, or it is not.

There is a set number of X, and as the number of winning tickets decrease, the probability of a winning ticket being held by a men can decrease or increase. This is a characteristic of the hypergeometric distribution.

5 0
2 years ago
Please Hurry! I will award the first person right the brainlyest award
Len [333]

Answer:

y = -3

Step-by-step explanation:

When you graph it on a graphing calculator or on desmos, it appears to be at y = -3

6 0
2 years ago
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(b) Her friend Hannah gets 70% of the 140 marks available in the exam.
Lisa [10]

\huge\fbox{Answer ☘}

number of marks available = 140

percentage secured = 70%

therefore marks secured =

70\% \:  \: of \: 140 \\\\  =>\frac{70}{100}  \times 140 \\ \\ =  > 98 \: marks

hope helpful~

5 0
2 years ago
The average length of a field goal in the National Football League is 38.4 yards, and the s. d. is 5.4 yards. Suppose a typical
Tasya [4]

Answer:

a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b) 0.25% probability that his average kicks is less than 36 yards

c) 0.11% probability that his average kicks is more than 41 yards

d-a) The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

d-b) 1.32% probability that his average kicks is less than 36 yards

d-c) 0.80% probability that his average kicks is more than 41 yards

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 38.4, \sigma = 5.4, n = 40, s = \frac{5.4}{\sqrt{40}} = 0.8538

a. What is the distribution of the sample mean? Why?

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 0.8538.

b. What is the probability that his average kicks is less than 36 yards?

This is the pvalue of Z when X = 36. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{0.8538}

Z = -2.81

Z = -2.81 has a pvalue of 0.0025

0.25% probability that his average kicks is less than 36 yards

c. What is the probability that his average kicks is more than 41 yards?

This is 1 subtracted by the pvalue of Z when X = 41. So

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{0.8538}

Z = 3.05

Z = 3.05 has a pvalue of 0.9989

1 - 0.9989 = 0.0011

0.11% probability that his average kicks is more than 41 yards

d. If the sample size is 25 in the above problem, what will be your answer to part (a) , (b)and (c)?

Now n = 25, s = \frac{5.4}{\sqrt{25}} = 1.08

So

a)

The sample is larger than 30, so, by the Central Limit Theorem, the distribution of the sample means will be normally distributed with mean 38.4 and standard deviation 1.08

b)

Z = \frac{X - \mu}{s}

Z = \frac{36 - 38.4}{1.08}

Z = -2.22

Z = -2.22 has a pvalue of 0.0132

1.32% probability that his average kicks is less than 36 yards

c)

Z = \frac{X - \mu}{s}

Z = \frac{41 - 38.4}{1.08}

Z = 2.41

Z = 2.41 has a pvalue of 0.9920

1 - 0.9920 = 0.0080

0.80% probability that his average kicks is more than 41 yards

4 0
3 years ago
2 Points<br> What is sin 60°
sweet-ann [11.9K]

Answer:

As in Decimal: 0.86602540378

Angle Tan=Sin/Cos

30°          1 √3 = √3 3

45°          1

60°     √3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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