Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.
Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8
Then set up the "point-slope form":
y - y0 = m * (x - x0)
You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.
x0 = 1
y0 = 10
Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)
The above equation will work fine for an answer, but let's go a step further and solve for y.
y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
y = -9/8x + 9/8 + 80/8
y = -9/8x + (9 + 80)/8
y = -9/8x + 89/8
Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
C = children
A = adults
293 = c + a
1.50c + 2.50a = 676.50
We can use substitution to solve:
c + a = 293 subtract a to get c = 293 - a
Plug this into the second equation:
1.50(293 - a) + 2.50a = 676.50
439.5 - 1.50a + 2.50a = 676.50
439.5 + 1a = 676.50
a = 237
Substitute this into the first equation:
293 = c + 237
56 = c
Answer:
An exterior angle=60°
An interior angle=120°
Step-by-step explanation:
Hexagon has 6 sides
Each exterior angle=360➗number of sides
Each exterior angle=360 ➗ 6
Each exterior angle=60°
Each interior angle=180-60
Each interior angle=120°
What goes in the empty box is 22 because they notes get multiplied by 2 to equal the time
