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Bumek [7]
2 years ago
11

Which one doesn’t represent a function?

Mathematics
1 answer:
Olenka [21]2 years ago
4 0
It’s 3. Each input can only go to one output and 2 goes to 2 outputs
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The answer is<br><br> 7 m5– 3 m3 + 0 m – 3
jarptica [38.1K]

Answer:

ok cool

Step-by-step explanation:

:)

3 0
3 years ago
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If 3(r+300)=6 then find the value of r+300-2
faltersainse [42]

Answer:

0

Step-by-step explanation:

3(r+300)=6

Divide each side by 3

3/3(r+300)=6/3

(r+300)=2

Now we want to find

r+300-2

2 -2

0

8 0
3 years ago
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A car, starting from a city, traveled east for 100 km and then west for
Vesnalui [34]
Microsoft maths somebody is saying
8 0
3 years ago
Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x
Greeley [361]

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

2^x=1-3^x

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

2^{-0.75}=1-3^{-0.75}

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

2^{-1.25}=1-3^{-1.25}

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

2^{0.75}=1-3^{0.75}

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

2^{1.25}=1-3^{1.25}

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

6 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
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