Answer:
2x + 2
Step-by-step explanation:
2x -2 + 2x + 3 is equal to 4x + 1 to make it 6x + 3 you need to add 2x to the term 4x and you need to add 2 to the term 1 so
2x + 2
Answer:
f(x) has three real roots and two imaginary roots.
Step-by-step explanation:
Given that three roots of a fifth degree polynomial function f(x) are -2,2 and (4+i).
Now we need to find about which of the given statements describes the number and nature of all roots for this function.
We know that imaginary roots always occur in conjugate pairs.
So if (4+i) is root then (4-i) must also be the root.
So now we have total 4 roots
-2, 2, (4+i) and (4-i).
Degree of the polynomial is 5 so that means 1 root is still remaining. It can't be imaginary as that must be in pairs
So that means 5th root is real.
Hence correct choice is :
f(x) has three real roots and two imaginary roots.
Answer:
(6x² - 5)(x² + 2)
Step-by-step explanation:
Given
6
- 5x² + 12x² - 10 ( factor the first/second and third/fourth terms )
= x²(6x² - 5) + 2(6x² - 5) ← factor out (6x² - 5) from each term
= (6x² - 5)(x² + 2)
A graphing calculator or spreadsheet program can do this for you. Below is a plot from the Desmos on-line graphing calculator.
Answer:
a) 1.
Step-by-step explanation:
Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.
Luego, el conjunto de los cinco enteros positivos se puede expresar como
A = {a; a+1; a+2; a+3; a+4}
Dada la condición del problema, se debe cumplir que
a + (a+1) + (a+2) = (a+3) + (a+4)
⇒ 3a + 3 = 2a + 7
Resolviendo la ecuación resulta
a = 4
Luego, el conjunto A nos resulta
A = {4; 5; 6; 7; 8}
Puede concluirse que sólo un conjunto cumple con esta condición.
