Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.
We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.
Therefore A ⊆ B.
Answer:
in mathematics, the sine is a trigonometric function of an angle.
Step-by-step explanation:
The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle to the length of the longest side of the triangle (the hypotenuse).
Fixed point: 0
Critical point: kπ + π/2
Inflection point: kπ hope this helps you :)
Answer:
see below
Step-by-step explanation:
The ASA congruence postulate is being invoked, so you're looking to show two angles and the side between them are congruent.
_____
Personally, I'd go at it differently. I'd say that alternate interior angles ∠C≅∠E means AE║CD, so ∠A≅∠D because they're alternate interior angles. B does not need to be a midpoint for this proof.