How to subrtact a negative from a negative?
2 answers:
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Answer:
1) Factor form :
2) 8 second after launch.
Step-by-step explanation:
The height of the ball (in meters above the ground) t seconds after launch is modeled by
To find the time when ball hit the ground, we need to find the factor form of the given function.
When ball hi the ground, then height of the ball from the ground is 0.
Using zero product property, we get
Ball hit the ground at t=0 and t=8. It means ball hit the ground in starting and 8 second after launch.
Answer:
x = 3 is extraneous
Step-by-step explanation:
Given
= x - 5 ( square both sides to clear the radical )
4x - 8 = (x - 5)² ← expand using FOIL
4x - 8 = x² - 10x + 25 ( subtract 4x - 8 from both sides )
0 = x² - 14x + 33 ← in standard form
0 = (x - 11)(x - 3) ← in factored form
Equate each factor to zero and solve for x
x - 11 = 0 ⇒ x = 11
x - 3 = 0 ⇒ x = 3
As a check
Substitute these values into the equation and if both sides are equal then they are solutions
x = 11
left side = =
= 6
right side = 11 - 5 = 6
Thus x = 11 is a solution
x = 3
left side = =
= 2
right side = 3 - 5 = - 2 ≠ 2
Thus x = 3 is an extraneous solution