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3 years ago

I was working on this question and and a bit confused, somebody plz help!! :)

Mathematics

2 answers:

ladessa [460]3 years ago

5 0

The answer should be 6s^3 because you add the two powers together since the number (6) is the same

pav-90 [236]3 years ago

3 0

Answer:

36s³

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

6s² × 6s

= 6 × s² × 6 × $s^{1}$

= 6 × 6 × s² × $s^{1}$

= 36 × $s^{(2+1)}$

= 36s³

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PLEASE ANSWER THIS QUESTION

EleoNora [17]

Answer:

-1

Step-by-step explanation:

because when y is 2, x is -1

4 0

3 years ago

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A man is sixteen years older than his father, if the total age is 57. How old is the son and the father?

Alex Ar [27]

Answer:

The son is 20 and a half years old.

The father is 36 and a half years old.

Step-by-step explanation:

We can solve this easily by turning it into an equation.

Let the mans age be y and the fathers age be x.

y+x=57

x=y+16

We can use the substitution method to solve for the first equation.

y+(y+16)=57

Now we only have one variable to solve for. Add like terms.

2y+16=57

Subtract 16 on both sides.

2y=41

Divide both sides by 2 to isolate y.

y=20.5

Now substitute 20.5 for y to solve for x.

20.5+x=57

Subtract 20.5 from both sides.

x=36.5

The son is 20 and a half years old.

The father is 36 and a half years old.

Hope this helps!

8 0

3 years ago

Fill in the blanks 3:4 = 6:_ = 9:_ = _:16 = _:20 = 18:_?????

Virty [35]

3:4 = 6:8 = 9:12 = 12:16 = 15:20 = 18:24

3 0

3 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$