The speed of the plane after it encounters the wind is C.285mph
<h3>How to calculate the speed of the plane when it encounters the wind?</h3>
Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j
= (320 × 0)i + (320 × -1)j
= 0i - 320j
= - 320j mph
Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph
So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'
= -320j mph + 35j mph
= -285j mph
So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph
= 285 mph
So, the speed of the plane after it encounters the wind is C.285mph
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Answer: 120
"A analog clock is diveded up into 12 sectors, based on the numbers 1-12. one sector represents 30 degrees (360/12=30). if the hour hand is directly on the 10, and the minute hand is on the 2, that means there are 4 sectors of 30 degree between then, thus they are 120 degree apart (30*4=120)."
Answer:
True
Step-by-step explanation:
In my opinion the following statement would be true. In order to become good at anything you need to practice, (also could mean hard work) and determination the drive to get good at the act you are working on. Some believe discipline would often be a good way to get good at something.
Hope this helps.
D. right
a right angle always equals a right triangle
Hey there!
840 = 100%
x = 17%
840/x = 100%/17%
(840/x) * x = (100/17) * x 840 = <span>5.8823529411765
</span>
<span>= 840/5.8823529411765 = 142.80
The correct answer to your question is option C.
The tip Christian should leave is $142.80.
Hope this helps you.
Have a great day!
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