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2 years ago

Earthquakes that occur far from plate boundaries are called

Biology

1 answer:

aivan3 [116]2 years ago

4 0

Answer:

intraplate' earthquakes

Explanation:

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Which of the following is/are the most specific internal defense against disease?

Dmitry [639]

Nk cells

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3 years ago

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Which disease is spread by mosquitoes?

Zolol [24]

Answer:

D) dengue fever

but answer may vary

Explanation:

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3 years ago

Taste receptors on the tongue are not related to smell receptors of the nose.

tekilochka [14]

Answer:

<u>b. False</u>

Explanation:

As human has about 350 olfactory receptors and subtypes work in various conditions allowing us to sense about 10,000 doors. All senses of smell and tastes merge at the back of the throat.

As you taste something before smelling it the smell lingers on inside in the nose which makes you smell it. As both the smell and taste are chemoreceptors which means both have chemically same sensing environments.

In addition, the division of taste receptors within the nose coordinate with activities, although humans can distinguish between the tastes from the smells of the objects.

Working together to create a perception of flavor through the nasal passage.

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3 years ago

Which of the following is a benefit of recreation activities?

9966 [12]

Answer:

C Noise pollution

Explanation:

because organisms create noise.

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3 years ago

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Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive gene 43) in humans. A woman whose fath

LiRa [457]

Answer:

50% or 1/2. The result remains unchanged if the husband were to have G6PD.

Explanation:

For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.

Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype $X^GX^g$ . A normal man will have the genotype $X^GY$ . When the 2 marries:

$X^GX^g$ x $X^GY$ = $X^GX^G (normal female), X^GY (normal male), X^GX^g (carrier female), X^gY (affected male)$ It thus means that 50% or 1/2 of their sons will be expected to have G6PD.

Now, assuming the husband has G6PD, the mating becomes:

$X^GX^g$ x $X^gY$ = $X^GX^g (carrier female), X^GY (normal male), X^gX^g (affected female), X^gY (affected male)$ 50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.

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3 years ago