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Greeley [361]
3 years ago
10

I tought of a number double it then added 3. The result multiplied by 4 came to 52,what was the number I tought of? ​

Mathematics
2 answers:
Crank3 years ago
7 0

Answer:

5

Step-by-step explanation:

double 5 is 10

10+3=13

13 multiplied by 4=52

Digiron [165]3 years ago
3 0
The original number you thought of was 5
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Solve for b:<br><br> b² = 8b + 84
levacccp [35]
B² = 8b + 84
b² - 8b - 84 = 0
b = <u>-(-8) +/- √((8)² - 4(1)(-84))</u> 
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</u>b = <u>8 +/- √(64 + 336)</u>
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b = <u>8 +/- √(400)
</u>               2<u>
</u>b = <u>8 +/- 20
</u>            2
b = 4 <u>+</u> 10
b = 4 + 10          b = 4 - 10
b = 14                b = -6
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4 0
3 years ago
Suppose you rolled a twelve-sided number cube instead of a standard six-sided one. How would the probability of these events cha
BlackZzzverrR [31]

Answer:

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5 0
3 years ago
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patsy's pizzeria sold 3 5/6 vegetables pizzas yesterday. they sold 3 times as many pepperoni pizzas. how many pepperoni pizzas d
dsp73

Answer:

11.5

Step-by-step explanation:

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8 0
3 years ago
How many lines of symmetry does the letter z have ?
JulijaS [17]

Answer:

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6 0
3 years ago
|2s|+19=13<br> Help me please
Mnenie [13.5K]

 \textsf{Hey there!}

\mathsf{|2s| + 19= 13}\\\textsf{Solve both sides by -19}\\\mathsf{|2s|+19+ (-19)=13+(-19)}\\\mathsf{Cancel\ out:\ 19 + (-19) \  because\ that\ gives\ you\ 0}\\\mathsf{Keep: 13 + (-19)\ because\ that\  helps\ us\ solve\ for\ our\ answer}\\\mathsf{13 + (-19) = -6}\\\mathsf{Solve\ for\ absolute\ value: |2s| = -6}\\\mathsf{Any\ absolute\ values\ CANNOT\ be\ less\ than\ 0}\\\mathsf{\boxed{\boxed{\mathsf{Thus, \ this\ make\ your\ answer\ is: \boxed{\boxed{\bf{No\ solution}}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

4 0
3 years ago
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