divide distance by speed
equation: time = distance / speed
120/8.5 = 14.117 seconds
Answer:
hi so im jeff wanna be my friends
Step-by-step explanation:
ANSWER

EXPLANATION
The given vector is v = −14.5i + 2.5 j.
The magnitude of this vector is



The unit vector in the direction of this vector is



Answer:
D
Step-by-step explanation:
Up to 400 pages, the cost is fixed at 5.00 dollars
After 400 pages the cost is 0.01 cents/page
- It's not A. 400 is the number of pages. It is not a cost.
- It's not B either. B means that no matter how many pages you print, it's going to cost 5 dollars + the number of pages times 1 cent.
- C is not the answer. It is really just an answer put it. You pay 1 cent for each page between 400 and what you printed.
- I think D is the answer, but if you get a negative number, then the cost is 5 dollars
Answer:
triangle KLM
Step-by-step explanation:
Take one point on the initial triangle and move it according to the given translation to locate the image. I used point G. Its coordinate plot is at
(2,3). I perform the operation of the given translation to this. (X1-X2, y1-y2).
So, (2-1, 3-8). The new coordinates will be (1,-5) and the only triangle with these coordinates is triangle KLM.