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Ilia_Sergeevich [38]
3 years ago
9

Tasha's scores on her first five tests were as follows. 74, 90, 92, 83, 81 What would Tasha have to score on the sixth test to h

ave a mean of 85?
Mathematics
2 answers:
Dafna1 [17]3 years ago
5 0

Answer:

it would be 90. Hope I helped

Step-by-step explanation:

Tpy6a [65]3 years ago
4 0
For this case, what we must do is calculate the mean of the given data.
 For this, we must do the following:
 Add the given numbers and divide by the number of numbers.
 We have then:
 \frac{74+90+92+83+81+x}{6}=85
 From here, we clear the value of x.
 We have then:
 x = 6 * 85 - (74 + 90 + 92 + 83 + 81)

x = 90
 Answer:
 
Tasha would have to score 90 on the sixth test to have a mean of 85
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"On a map, 0.25 inches represents 1 mile. What is the area of a rectangle on the map that is 3.75 inches long and 2.25 inches wi
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0.25 inches represents 1 mile

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Find 1 inch:
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1 inch represents 1 ÷ 0.25 miles
1 inch represents 4 miles

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Please help me answer one of these!
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This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



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