The average rate of change of the function at the interval is -8
<h3>How to determine the average rate of change?</h3>
The table that completes the question is added as an attachment
From the table, we have:
f(5) = -26
f(3) = -10
The average rate is then calculated as:
Rate = (f(5) - f(3))/(5 -3)
This gives
Rate = (-26 + 10)/(5 -3)
Evaluate
Rate = -8
Hence, the average rate of change of the function is -8
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The exponential function is defined as y = a(1+r)^x, where "a" represents the original account and "r" the rate of growth or decay.
Then we have the following:
1) 22% grow
y = a( 1 + 22%/100 )^x = a(1.22)^x
So the solution is: 124(1.22)^x
2) 12% decay
y = a( 1 - 12%/100 )^x = a(0.88)^x
So the solution is: y = f(x) = 44(0.88)^x
3) 20% decay
y = a( 1 - 20%/100 )^x = a(0.8)^x
So the solution is: f(x) = 22(0.8)
4) 12% Groth
y = a( 1 + 12%/100 )^x = a(1.12)^x
So the solution is: f(x) = 42(1.12)^x
Hello,
P=0.2 Mass=22 so that means that T would =253
Hope this helps
Answer:
3x-5 and r=0
Step-by-step explanation:
We can do it by long division method the required quotient is 3x-5 and r=0
not 3x-1 , r=1
multiply the divisor with 3x we will get to cancel out the first term of dividend
Now after solving we will get
Now, multiply the divisor by -5 we will get -5x-15 which will cancel the entire dividend.
Answer:
Step-by-step explanation:
dy/dx = d/dx log root under x-1 / root under x+1
dy/dx = root under x+1 / root under x-1 * 1/(x+1)^2/3 * 1/root under x-1
dy/dx = (x+1)^2/ x-1
