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Snowcat [4.5K]
3 years ago
13

At a candy store you can pay $16.10 for 7 giant lollipop what would be the cost for 6 lollipops?

Mathematics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer: $13.80 for 6 giant lollipops

Step-by-step explanation: To find the cost of 6 giant lollipops at the candy store, we first need to find the unit price for a giant lollipop.

Unit price means the cost per unit,

in this case, the cost per giant lollipop.

Since we know that it costs $16.10 for 7 giant lollipops, to find the cost

for 1 giant lollipop, we need to 16.10 by 7.

16.10 divided by 7 is 2.3.

This means that each lollipop is $2.30.

Now to find the cost for 6, we multiply

the cost per 1 lollipop by 6.

So we have 2.30 × 6 which is $13.80.

So the cost for 6 lollipops at the candy store is $13.80.

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as a gift, you fill the calendar with packets of chocolate candy. Each packet has a volume of 2 cubic inches. Find the maximum n
qaws [65]
The picture of the calendar is shown in the attached image.

Now, first we will get the volume of the calendar itself, we can note the calendar has the shape of a triangular prism.
Volume of triangular prism = area of base * depth
The area of base = area of triangle = 1/2 * base * depth 
Therefore:
Volume of prism = 1/2 * base * height * depth
where:
base = 4 in
height is he height of the base = 6 in
depth is the depth of the calendar = 8 in
Therefore:
Volume of calendar = 1/2 * 4 * 6 * 8 = 96 in^3

Now, we are given that the volume of each candy is 2 in^3, this means that:
number of candies to fill the calendar = volume of calendar / volume of candy
                                                            = 96/2 
                                                            = 48 candies

Hope this helps :)

4 0
3 years ago
What is vaule of f^-1 (-4)
Butoxors [25]

Answer:

-4/f

Step-by-step explanation:

i hope this helps

hi

5 0
3 years ago
Mr.Ramirez teaches dance. He has 16 sixth-grade students and 24 seventh-grade students. He wants to put the students in equal gr
Dahasolnce [82]
Mr. Ramirez can use many different group sizes, but the largest group size possible is 8.  This results in 16/8=2 sixth-grade groups and 24/8=3 seventh-grade groups.
6 0
3 years ago
Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×
strojnjashka [21]
8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number

Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n

(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n

So the ASTM grain size number is 8.9

If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458

Or about 2,400,000 grains per square inch.
7 0
3 years ago
The distribution of the time it takes for different people to solve a certain crossword puzzle is strongly skewed to the right,
dezoksy [38]
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5 0
3 years ago
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