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The answer is C.
Since here taxable income is over $77,100 and below $160,850, her tax is $15,698.75 + [.28*($95,000 - $77,100)].
Tax = $15,698.75 + [.28*($17,900)]<span>.
= </span>$15,698.75 + [$5012]<span>.
=</span><span> $</span><span>20,710.75
Thank you for posting this question. Please feel free to ask me more.</span>
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
y=3x-1
Step-by-step explanation:
Hey there!
We are looking for the circumference of the circle, which is the distance around it. We are given the area, which is the radius squared times pi.
First, we need to undo the area to find our radius.
113.04/3.14=36
We square root this to find the radius.
√36=6
Our radius is six. To find the circumference, we need to multiply the diameter by pi. The diameter is twice the radius.
6*2=12
12*3.14=37.68
Therefore, we will need 37.68 feet of trim to around the edge of the quilt.
I hope this helps!
