On 3 and 6 you did not clarify whether it is addition, subtraction, multiplication, or division.
Therefore, I have worked out all possible solutions.
If 2(3 - 6 x 3 - 5) then the solution is 12.<span>
If 2(3 + 6 x 3 - 5) then the solution is -36.</span><span>
If 2(3 / 6 x 3 - 5) then the solution is -2.
If 2(3 x 6 x 3 - 5) then the solution is -72.</span>
Answer: c) 
.
Step-by-step explanation:
Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that
Given function : 
Interval : [0,3]
Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that
Since 
then, at x=c, 
From (i) and (ii), we have
Hence, the correct option is c) .
Step-by-step explanation:
Simplify the following:
(((-3)/4)^5)^2
Multiply exponents. (((-3)/4)^5)^2 = ((-3)/4)^(5×2):
((-3)/4)^(5×2)
5×2 = 10:
((-3)/4)^10
((-3)/4)^10 = (-3)^10/4^10:
(-3)^10/4^10
(-3)^10 = (-1)^10×3^10 = 1×3^10:
3^10/4^10
4^10 = (4^5)^2 = (4×4^4)^2 = (4 (4^2)^2)^2:
3^10/(4 (4^2)^2)^2
4^2 = 16:
3^10/(4×16^2)^2
3^10/(4×256)^2
4×256 = 1024:
3^10/1024^2
3^10/1048576
Answer=3^10 / 2^20
