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3 years ago

Calculate the length of line AB

Mathematics

1 answer:

amid [387]3 years ago

7 0

See the picture, using Pythagorean’s theorem

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Yukiko plays on the softball team at her school. The team won 9 of its first

Blababa [14]

Answer:

Step-by-step explanation:

9/12 is the ratio of wins. after simplifing it, you get 3/4. You can use that to find the wins after 64 games. Divide 64 by 4 and multiply that by 3. The answer is 48 game wins after 64 games played.

4 0

3 years ago

Read 2 more answers

Estimate the surface area of a cube with side length 9.9 in

Igoryamba

The answer would be C) 600 in2.

4 0

3 years ago

Read 2 more answers

What is the solutions set

oksian1 [2.3K]

2x< -9 +1
2x< -8
x< - 8/2
x< - 4

3x> 2 - 5
3x > - 3
x> -3/3
x > -1

the third is the answer

8 0

3 years ago

HELP PLEASE solve for x : 2.1x - 3.6 = 8 1) 6.77 2)2.1 3)1.22 4)5.52

ss7ja [257]

Answer:

Rounding x = 5.52

Step-by-step explanation:

2.1x - 3.6 = 8

Add 3.6 to each side

2.1x - 3.6+3.6 = 8+3.6

2.1x = 11.6

Divide each side by 2.1

2.1x/2.1 = 11.6/2.1

x =5.523809524

Rounding x = 5.52

3 0

3 years ago

2. A geological study indicates that an exploratory oil well drilled in a particular region should strike oil with probability 0

yKpoI14uk [10]

Answer:

3.07% probability that the third oil strike comes on the fifth well drilled.

Step-by-step explanation:

For each oil drill, there are only two possible outcomes. Either there is a strike, or there is not. The probability that oil is striken in a trial is independent of other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Strike oil with probability 0.20.

This means that $p = 0.2$

Find the probability that the third oil strike comes on the fifth well drilled.

2 strikes on the first four drills(P(X = 2) when n = 4) and strike on the fifth(0.2 probability).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.2)^{2}.(0.8)^{2} = 0.1536$

0.2*0.1536 = 0.0307

3.07% probability that the third oil strike comes on the fifth well drilled.

8 0

3 years ago