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daser333 [38]
3 years ago
14

6t - 20 - 32u when t = 6 and u 1/4

Mathematics
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

8

Step-by-step explanation:

6(6) - 20 - 32 (1/4)

36 -20 - 8

16 - 8

8.

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Susan is looking to hire a cleaning company to clean her house every week. One cleaning company's cost can be calculated by the
kirill [66]

Answer:

<h3>A. 1 hour</h3>

Step-by-step explanation:

If one cleaning company's cost can be calculated by the expression 75 + 50x, where x is the amount of hours they spend cleaning and another cleaning company's cost can be calculated using the expression 50 + 75x, then to calculate how long each company will have to clean to cost the same amount, we will equate both expression of the company cost and solve for x as shown;

On equating:

75 + 50x,  =  75x + 50

collect like terms'

50x-75x = 50-75

-25x = -25

divide both sides by -25

-25x/-25 = -25/-25

x = 1

hence the number of hours each company will have to clean to cost the same amount is 1 hour

3 0
3 years ago
Prove that the value of the expression: (125^2+25^2)(5^2–1) is divisible by 39
prisoha [69]

Answer:

(1252+252)(52−1)

=(1252+252)(52+−1)

=(1252)(52)+(1252)(−1)+(252)(52)+(252)(−1)

=390625−15625+15625−625

=390000

divide by 39 is

=10000

4 0
3 years ago
Simplify:(y²+z²) -2yz​
VMariaS [17]

Answer:

  (y-z)^{2}

Step-by-step explanation:

  (y^{2}+z^{2} ) -2yz\\\\y^{2} +z^{2} - 2yz\\\\y^{2} +2yz + z^{2}\\\\(y-z)^2\\

5 0
3 years ago
Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ
slega [8]
Using the law of cosine for Triangle KJL, we can write:

j^{2} = k^{2} + l^{2}-2(k)(l)cos(J)  \\  \\ &#10;2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\  \\ &#10;cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}

Using the values of k,j and l, we can write:

cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)}  \\  \\ &#10;cos(J)= 0.664 \\  \\ &#10;J= cos^{-1}(0.664) \\  \\ &#10;J=48.39

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer
8 0
3 years ago
Read 2 more answers
Make s, u subject of the formula<br><img src="https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20u%20%7B%7D%5E%7B2%7D%20%2B%202as" id="
Romashka [77]

Answer:

s = \frac{v^2-u^2}{2a}

Step-by-step explanation:

Given

v² = u² + 2as ( subtract u² from both sides )

v² - u² = 2as ( divide both sides by 2a )

\frac{v^2-u^2}{2a} = s

Given

v² = u² + 2as ( subtract 2as from both sides )

v² - 2as = u² ( take the square root of both sides )

± \sqrt{v^2-2as} = u

6 0
3 years ago
Read 2 more answers
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