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Serjik [45]
3 years ago
13

H(x)= (x^2 -36)/x +6 explain why the following function is not continuous at x=-6

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

You can solve this problem through factoring.

First, you have the equation,

h(x) = \frac{x^2-36}{x-6}

Then, you can factor the numerator.

h(x) = \frac{(x+6)(x-6)}{x-6}

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.

You are left with h(x) = x+6

The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.

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You buy milk that contains 180 calories per 2 cups. Use a ratio table to find the number of calories in 5.5 cups.
Ludmilka [50]

Answer:

The number of calories in 5.5 cups are <u>495</u>.

Step-by-step explanation:

Given:

You buy milk that contains 180 calories per 2 cups.

Now, to find the number of calories in 5.5 cups.

Let the number of calories in 5.5 cups be x.

As, in 2 cups there are 180 calories.

2 cups is equivalent to 180 calories.

Thus, the ratio would be 2:180.

So, in 5.5 cups there are x calories.

5.5 cups is equivalent to x calories.

Thus, the ratio would be 5.5:x.

Now, we set proportion to get the number of calories in 5.5 cups:

2:180::5.5:x

\frac{2}{180} =\frac{5.5}{x}

<em>By cross multiplying we get:</em>

2x=990

<em>Dividing both sides by 2 we get:</em>

x=495.

Therefore, the number of calories in 5.5 cups are 495.

4 0
4 years ago
Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
A room contains three urns: u1, u2, u3. u1 contains 3 red and 2 yellow marbles. u2 contains 3 red and 7 yellow marbles. u3 conta
Archy [21]

Answer:

\dfrac{11}{30}

Step-by-step explanation:

Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{3}{5}=0.6.

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is \dfrac{3}{10}=0.3.

Urn U1: 1 red and 4 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{1}{5}=0.2.

The probability to choose each urn is the same and is equal to \frac{1}{3}.

Thus, the probability that the marble is red is

\dfrac{1}{3}\cdot 0.6+\dfrac{1}{3}\cdot 0.3+\dfrac{1}{3}\cdot 0.2=\dfrac{1.1}{3}=\dfrac{11}{30}.

4 0
3 years ago
What do you add to 4 1/8 to make it 6
svp [43]

Answer:

1 7/8

Step-by-step explanation:

6 - 4 1/8

2 - 1/8

15/8 = 1 7/8

8 0
3 years ago
Read 2 more answers
(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde
monitta

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2  } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2}  \\d=\sqrt{36+4} \\d=\sqrt{40} \\

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0
3 years ago
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