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Serjik [45]
3 years ago
13

H(x)= (x^2 -36)/x +6 explain why the following function is not continuous at x=-6

Mathematics
1 answer:
sergeinik [125]3 years ago
8 0

You can solve this problem through factoring.

First, you have the equation,

h(x) = \frac{x^2-36}{x-6}

Then, you can factor the numerator.

h(x) = \frac{(x+6)(x-6)}{x-6}

You can cancel out the x-6 in both the numerator and the denominator because they would equal to just 1.

You are left with h(x) = x+6

The function is removable noncontinuous at x=6 because if you plug in 6 in x-6, your denominator would be undefined.

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