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Rashid [163]
3 years ago
5

Help me? please?????????

Mathematics
2 answers:
bagirrra123 [75]3 years ago
3 0
8/63 is the simplest form of the fraction
Andrews [41]3 years ago
3 0

Answer:

\huge\boxed{\tt{\frac{8}{63} }}

Step-by-step explanation:

\displaystyle \frac{8}{9} * \frac{1}{7} \\\\= \frac{8*1}{9*7} \\\\= \frac{8}{63} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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The answer of the question is 125
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4 years ago
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An urn contains 5 red, 6 blue, and 8 green balls. If a set of 3 balls is randomly selected, what is the probability that each of
monitta

Answer:

As a fraction, the answer is exactly 86/969

In decimal form, the answer is approximately 0.08875

=====================================================

Work Shown:

The assumption is that no replacements are made for each selection.

5 red, 6 blue, 8 green

5+6+8 = 19 total

A = P(3 red) = (5/19)*(4/18)*(3/17) = 10/969

B = P(3 blue) = (6/19)*(5/18)*(4/17) = 20/969

C = P(3 green) = (8/19)*(7/18)*(6/17) = 56/969

D = P(3 all same color)

D = A+B+C

D = 10/969 + 20/969 + 56/969

D = (10+20+56)/969

D = 86/969

D = 0.08875

6 0
3 years ago
A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
Wittaler [7]

Answer: 18.75 lb.ft

Step-by-step explanation:

Given

Force required to stretch spring 8 in. is 18 lb

it can be written

\Rightarrow F=kx\\\Rightarrow 18=k(8)\\\\\Rightarrow k=\dfrac{18}{8}=\dfrac{9}{2}\ lb/in.

Work done in stretching from its natural length to 10 in.

\Rightarrow W=\dfrac{1}{2}kx^2\\\\\Rightarrow W=0.5\times \dfrac{9}{2}\times (10)^2\\\\\Rightarrow W=225\ lb.in.\ or\\\Rightarrow W=18.75\ lb.ft

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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